简单题

#include 
      
       #include 
       
        #include 
        
         #include 
         
          using namespace std;#define maxn 1005int n;int f[maxn];double average;void input(){    int sum = 0;    scanf("%d", &n);    for (int i = 0; i < n; i++)    {        scanf("%d", &f[i]);        sum += f[i];    }    average = sum * 1.0 / n;}double work(){    int num = 0;    for (int i = 0; i < n; i++)        if (f[i] > average)            num++;    return num * 100.0 / n;}int main(){    int t;    scanf("%d", &t);    while (t--)    {        input();        printf("%.3f%%\n", work());    }    return 0;}